A 0.2-kilogram softball is thrown toward a catcher's mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher's mitt? (1 point)

Question

8.2 N

7.8 N

40 N

1.6 N

Answer 1

To calculate the force exerted by the softball, we can use Newton's second law of motion, which states that \( F = ma \), where \( F \) is the force, \( m \) is the mass of the object, and \( a \) is the acceleration.

Given:

• Mass \( m = 0.2 \) kg
• Acceleration \( a = 8 \) m/s²

Now we can substitute these values into the equation:

\[ F = ma = (0.2 , \text{kg}) \times (8 , \text{m/s}^2) = 1.6 , \text{N} \]

So, the force with which the ball will hit the catcher's mitt is 1.6 N.