a 0.15 kg ball is thrown into the air & rises to a height of 20.0 m. how much kinetic energy did the ball initially have? ? ?

Answer 1

Vo^2 = Vf^2 - 2g*d.
Vo^2 = 0 -(-19.6)*20 = 392.
Vo = 19.8 m/s.
KE = 0.5m*V^2 = 0.075 * (19.8)^2 = 29.4
Joules.

Answer 2

thankss . what does the ^ mean tho ?

Answer 3

to the power of...