A 0.105 kg meter stick is supported at its 40 cm mark by a string attached to the ceiling. A 0.77 kg object hangs vertically from the 6.33 cm mark. A second mass is attached at another mark to keep it horizontal and in rotational and translational equilibrium. If the tension in the string attached to the ceiling is 21.3 N, ﬁnd the value of the second mass. The acceleration of gravity is 9.8 m/s2. Answer in units of kg Part 2 Find the mark at which the second mass is attached. Answer in units of cm

Question

A 0.105 kg meter stick is supported at its 40 cm mark by a string attached to the ceiling. A 0.77 kg object hangs vertically from the 6.33 cm mark. A second mass is attached at another mark to keep it horizontal and in rotational and translational equilibrium. If the tension in the string attached to the ceiling is 21.3 N, ﬁnd the value of the second mass. The acceleration of gravity is 9.8 m/s2. Answer in units of kg Part 2 Find the mark at which the second mass is attached. Answer in units of cm

bobpursley · Answer

First, sum force vertical. Let up be +
-.77g+21.3g-.105-M=0 solve for M, the unknown mass.

Now, to find the mark. Sum moments about any point. I choose the 0 mark at the end. Clockwise moments are +
6.33*.77-40*21.3+Massabove*Mark+50*.105=0
solve for Mark.

amanda and leah · Answer

the sum of foce doesn't work-- can you arrange it in a sum of Torque please?!?!?!?!

amanda and leah · Answer

the sum of foce doesn't work-- can you arrange it in a sum of Torque please?!?!?!?! and can you please rearrange the last part