dE - q _ w
w = -340 J
dE = 8450 J
Solve for q.
q = mass gas x specific heat x (Tfinal-Tinitial)
Substitute and solve for specific heat.
A 0.0800-kilogram sample of a gas is heated from 25°C to 225°C. During this process, 340 J of work is done by the gas and its internal energy increases by 8450 J. How much heat is transferred to the gas?
What is the specific heat of the gas for this process?(J/(Kg.K))
1 answer