A 0.025kg rubber stopper is swung in a horizontal circle by a 0.95 meter threat that makes 25 revolutions every 15 minutes. a) what is the stoppers speed? b) what is the acceleration? c) what is the value of the centripetal force?
4 answers
sorry not minutes but 15 seconds
T = 15/25 = .6 second
C = 2 pi R = 2 * 3.14 * .95 = 5.97 meter
a) v = C/T = 9.94 m/s
b) v^2/R = 9.94^2/.95 = 104 m/s^2
wow, 10 g
c) F = m a = .025*104 = 2.6 Newtons
C = 2 pi R = 2 * 3.14 * .95 = 5.97 meter
a) v = C/T = 9.94 m/s
b) v^2/R = 9.94^2/.95 = 104 m/s^2
wow, 10 g
c) F = m a = .025*104 = 2.6 Newtons
thank you for your help
You are welcome.