A 0.0170 M solution of an acid has a pH of 2.5. What is the pKa?

i did 10^-2.5=3.16e-3

Then 0.0170 - 3.16e-3=0.01384

ka= (3.16e-3)^2 / 0.01384 = 7.21e-4

pKa = -log(7.21e-4) = 3.14

The pKa is 3.14

Would you agree?

3 answers

Very good work.

Thank you!

please can I get a more detailed solution