A 0.0170 M solution of an acid has a pH of 2.5. What is the pKa?
i did 10^-2.5=3.16e-3
Then 0.0170 - 3.16e-3=0.01384
ka= (3.16e-3)^2 / 0.01384 = 7.21e-4
pKa = -log(7.21e-4) = 3.14
The pKa is 3.14
Would you agree?
3 answers
Very good work.
Thank you!
please can I get a more detailed solution