A 0.013 kg rubber stopper attached to a 0.93 m string is swung in a circle. If the tension in the string is 0.70 N, what is the period of the stopper's revolution?

1 answer

Ac = v^2/r
so
.7 = .013 v^2/.93

solve for v
we know r

time = distance / speed = 2 pi r/v