Ask a New Question

A 0.013 kg rubber stopper attached to a 0.93 m string is swung in a circle. If the tension in the string is 0.70 N, what is the period of the stopper's revolution?

1 answer

Ac = v^2/r
so
.7 = .013 v^2/.93

solve for v
we know r

time = distance / speed = 2 pi r/v

Ask a New Question or answer this question.

Similar Questions

1.13g plastic stopper is attached to a 0.93-m string. The stopper is swung in a horizontal circle, making one revolution in
1. 2 answers
A rubber stopper with a mass of 50.0 g attached to a string is being rotated in a vertical circle with a radius of 0.72 m at a
1. 1 answer
A stopper tied to the end of a string is swung in a horizontal circle. If the mass of the stopper is 13.0 g, and the string is
1. 1 answer
A stopper tied to the end of a string is swung in a horizontal circle. If the mass of the stopper is 13.0 g, and the string is
1. 1 answer

more similar questions