.........HX | H2O ==> H3O^+ X^-
I.......0.001..........0.....0
C........-x...........x......x
E......0.001-x........x......x
Ka = (H3O^+)(X^-)/(HX)
(H3O^+) = 0.001*0.06
(X^-) = 0.001*0.06
(HX) = (0.001-(0.001*0.06)
A 0.00100 M solution of a weak acid HX is 6% ionized. Calculate Ka for the acid.
1 answer