(9x^2-6x+2) - (x^2+4x-39)

Question

the difference between polynomials is?

Answer 1

To find the difference between the polynomials \((9x^2 - 6x + 2)\) and \((x^2 + 4x - 39)\), we can subtract the second polynomial from the first:

\[ (9x^2 - 6x + 2) - (x^2 + 4x - 39) \]

Distributing the negative sign across the second polynomial, we get:

\[ 9x^2 - 6x + 2 - x^2 - 4x + 39 \]

Now, we can combine like terms:

1. Combine \(9x^2\) and \(-x^2\): \[ 9x^2 - x^2 = 8x^2 \]

2. Combine \(-6x\) and \(-4x\): \[ -6x - 4x = -10x \]

3. Combine \(2\) and \(39\): \[ 2 + 39 = 41 \]

Putting it all together, the result is:

\[ 8x^2 - 10x + 41 \]

Thus, the difference between the polynomials is:

\[ \boxed{8x^2 - 10x + 41} \]

Answer 2

theres only supposed to be one sum

Answer 3

Apologies for any confusion! Let's clarify the subtraction of the two polynomials step by step and focus on combining the terms correctly:

We start with:

\[ (9x^2 - 6x + 2) - (x^2 + 4x - 39) \]

Distributing the negative:

\[ 9x^2 - 6x + 2 - x^2 - 4x + 39 \]

Now, combining like terms:

1. For \(x^2\) terms: \[ 9x^2 - x^2 = 8x^2 \]

2. For \(x\) terms: \[ -6x - 4x = -10x \]

3. For constant terms: \[ 2 + 39 = 41 \]

So, combining everything, we have:

\[ 8x^2 - 10x + 41 \]

The result is indeed a single polynomial expression, which is:

\[ \boxed{8x^2 - 10x + 41} \]

I hope this clarifies the answer! If you need further assistance or additional information, feel free to ask.