9x^2+4x+7=3x^2-8 How do I solve this?
3 answers
9x^2+4x+7=3x^2-8 How do I solve this?
9x^2+4x+7=3x^2-8
subtract 3x² from each side:
6x²+4x+7=-8
add 8 to each side:
6x²+4x+15=0
It turns out that the equation does not have real roots, just complex roots:
x=(2±sqrt(86))/6
subtract 3x² from each side:
6x²+4x+7=-8
add 8 to each side:
6x²+4x+15=0
It turns out that the equation does not have real roots, just complex roots:
x=(2±sqrt(86))/6
It turns out that the equation does not have real roots, just complex roots:
x=(-2±sqrt(86))/6
x=(-2±sqrt(86))/6