complete the square ...
9x^2 + 16y^2 - 36x + 96y + 36 = 0
9(x^2 - 4x + ...) + 16(y^2 + 6y + ..) = -36
9(x^2 - 4x + 4) + 16(y^2 + 6y + 9) = -36 +36+144
9(x-2)^2 + 16(y+3)^2 = 144
(x-2)^2/16 + (y+3)^2/9 = 1
so isn't a=4 and b=3 ?
9x^2 + 16y^2 - 36x + 96y + 36 = 0 How do i find the major axis?
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