9t^2-3t=0. Solve using quadratic formula

Answer 1

if the constant is missing, there is no need to use the formula, since the equation will always factor
9t^2 - 3t = 0
3t(3t-1) = 0
t = 0 or t = 1/3

if you insist ....
a = 9, b = -3, c = 0
x = (3 ± √(9-0)/18
= (3±3)/18
= 1/3 or 0