Asked by rida
The air in the syringe is at a pressure of 2.0×105Pa. The piston is slowly moved into the
syringe, keeping the temperature constant, until the volume of the air is reduced from
80 cm3 to 25 cm3. Calculate the final pressure of the air.
syringe, keeping the temperature constant, until the volume of the air is reduced from
80 cm3 to 25 cm3. Calculate the final pressure of the air.
Answers
Answered by
Damon
P V = n R T
n R and T do not change so
P1 V1 = P2 V2
2 *10^5 * 80 = P2 * 25
so
P2 = 2*10^5 * (80/25)
n R and T do not change so
P1 V1 = P2 V2
2 *10^5 * 80 = P2 * 25
so
P2 = 2*10^5 * (80/25)
Answered by
Anonymous
The air in the syringe is at a pressure of 2.0 X10^5 Pa. The piston is slowly moved into the syringe,
keeping the temperature constant, until the volume of the air is reduced from 80 cm^3 to 25 cm^3.
Calculate the final pressure of the air
keeping the temperature constant, until the volume of the air is reduced from 80 cm^3 to 25 cm^3.
Calculate the final pressure of the air
Answered by
Really
E3
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