Asked by rida

The air in the syringe is at a pressure of 2.0×105Pa. The piston is slowly moved into the
syringe, keeping the temperature constant, until the volume of the air is reduced from
80 cm3 to 25 cm3. Calculate the final pressure of the air.

Answers

Answered by Damon
P V = n R T

n R and T do not change so

P1 V1 = P2 V2

2 *10^5 * 80 = P2 * 25
so
P2 = 2*10^5 * (80/25)
Answered by Anonymous
The air in the syringe is at a pressure of 2.0 X10^5 Pa. The piston is slowly moved into the syringe,

keeping the temperature constant, until the volume of the air is reduced from 80 cm^3 to 25 cm^3.

Calculate the final pressure of the air
Answered by Really
E3
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