Question

A 15 kg mass, tied to the end of a 0.5 m long steel wire, is whirled in a vertical circle. The cross- section of the wire is 0.02 cm2. When the mass is at the bottom of the circle, its angular velocity is 2 rev s i. Find the elongation of the wire at this point.

Answer 1

Y=2•10¹¹ Pa
ω=2πf =2π•2=4π rad/s.

ma=T-mg
m ω²R =T – mg
T=m(ω²R+g) =m(16π²R +g)=…

T/A =Y•ΔL/L
ΔL=TL/AY =…