Question

for my homework problem i have the equation:

(x^2/16) + (y^2/4) = 1

I need to find out the center, the vertices, co- vertices and the Foci.

I have trouble knowing how to find them, so if you can please explain them.

Thank you.

Answer 1

in general

x^2/a^2 + y^2/b^2 = 1 is an ellipse with centre (0,0)
vertices (a,0) and (-a,0)
"co-vertices" (0,b), (0,-b)

foci : (c,0) and (-c,0) where c^2 = a^2 - b^2

your text should have that information for you.
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