Asked by Miley
A line has x-intercept (5, 0) and is perpendicular to the line 2x + 8y = 10. Find the y-intercept of the line.
Answers
Answered by
Reiny
your given line of 2x + 8y = 10 has slope -2/8 or -1/4
so the slope of a perpendicular line is +4
its equation is y = 4x + b, but (5,0) lies on it, so
0 = 4(5) + b
b = -20
new equation: y = 4x - 20
and the y-intercept is -20, (since we have it in slope y-intercept form)
so the slope of a perpendicular line is +4
its equation is y = 4x + b, but (5,0) lies on it, so
0 = 4(5) + b
b = -20
new equation: y = 4x - 20
and the y-intercept is -20, (since we have it in slope y-intercept form)
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