Asked by ms.sue help
Given: Rectangle ABCD with coordinates A(0, 0),
B(0, 8), C(5, 8), and D(5, 0). E is mdpt. of BC, and
F is mdpt. of AD.
Prove: EF = AB
B(0, 8), C(5, 8), and D(5, 0). E is mdpt. of BC, and
F is mdpt. of AD.
Prove: EF = AB
Answers
Answered by
Reiny
Did you sketch it ?
AB= √(0^2 + 8^2) = 8
F is (5/2,8)
E is (5/2, 0)
FE = √( (5/2-5/2)^2 + (8-0)^2 )
= √(0 + 64) = 8
so AB = EF
AB= √(0^2 + 8^2) = 8
F is (5/2,8)
E is (5/2, 0)
FE = √( (5/2-5/2)^2 + (8-0)^2 )
= √(0 + 64) = 8
so AB = EF