Asked by Harold

What is the minumum acceleration potential (V) that must be applied to a beam of free electrons for diffraction to occur in a crystal of niobium (Nb)? Express your answer in volts.
Answered by Harold
Any ideas?
Answered by Dick
2.6 *10^3 Volts
Answered by Dick
2.7*10^3, sorry
Answered by KS
Dude its wrong again
Answered by Anonymous
Nb is BCC and if you solve it, it gives you 2667 Volts but when you put it as your answer it gives X mark :(
Answered by Anonymous
My solution
if BCC first plane to give maximum wavelenth is (110) plane.

Then use lambda = 2dsin(theta) but since you want to maximize the lamdba assume that (theta) = 90 degrees

So lambda = 2d only

d = a(lattice constant) / sqrt (h^2 + k+2 + l^2)

solve for a, plug in (110) for (hkl)

then use lambda = hc/eV

to solve for Volts
Answered by Peter
Has anyone the right answer?
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