Asked by Anonymous
A wire that is 0.86 meters long is moved perpendicularly through a constant magnetic field of strength 0.035 newtons/amp·meter at a speed of 6.0 meters/second. What is the emf produced?
Answers
Answered by
bobpursley
area swept out: .86x6*timeinseconds
or 5.16m^2/sec
E=BdA/dt=.035*.86*6 volts
or 5.16m^2/sec
E=BdA/dt=.035*.86*6 volts
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