Asked by peter
If # (a,b,c,d)means you raise b,c and d to the power of a and then take the sum of the resulting values, and # (2,3,4,d)=89,then d=?
2^a + 3^a + 4^a = 89
1^a + 1^a + 1^a = 89
3^a = 89
a = 86
an I do it right
2^a + 3^a + 4^a = 89
1^a + 1^a + 1^a = 89
3^a = 89
a = 86
an I do it right
Answers
Answered by
peter
If # (a,b,c,d)means you raise b,c and d to the power of d and then take the sum of the resulting values, and # (2,3,4,d)=89,then d=?
2^d + 3^d + 4^d = 89
1^d + 1^d + 1^d = 89
3^d = 89
d = 86
2^d + 3^d + 4^d = 89
1^d + 1^d + 1^d = 89
3^d = 89
d = 86
Answered by
peter
If # (a,b,c,d)means you raise b,c and d to the power of a and then take the sum of the resulting values, and # (2,3,4,d)=89,then d=?
a. 8
b. 9
c. 64
d. 81
e. 90
please answer and explain
a. 8
b. 9
c. 64
d. 81
e. 90
please answer and explain
Answered by
peter
2 + 3^a + 4^a + d^a = 89
2 + 1^a + 1^a + d^a = 89
2^a + d^a = 87
2 + 1^a + 1^a + d^a = 89
2^a + d^a = 87
Answered by
peter
I don't know how to do
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.