The measurement of the edge of a cube is found to be 15 inches, with a possible error of 0.03 inch. Use differentials to approximate the maximum possible propagated error in computing the surface area of the cube.
I got 5.4 inches squared. Is this right?
5 answers
Hey, I did this
30) The measurement of the edge of a cube is found to be 15 inches, with a possible error of 0.03 inch. Use differentials to approximate the maximum possible propagated error in computing the volume of the cube.
MY ANSWER: 20.25
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v = x^3
dv = 3 x^2 dx
dv = 3 (225)(.03) = 20.25 right
MY ANSWER: 20.25
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v = x^3
dv = 3 x^2 dx
dv = 3 (225)(.03) = 20.25 right
No, it is 20.25 like you got in the first place.
No, this is a different part of that same problem. It asks for the surface area this time, not volume.
Oh, sorry !
1 answer