Constant v = 2πR/T=2π•7.3/34 = 1.3 m/s
Constant centripetal acceleration is
a=v²/R =1.3²/7.3 = 0.23 m/s²
A particle P travels with constant speed in a circle of radius 7.3 m and completes one revolution in 34.0 s (see Figure). The particle passes through O at t = 0 s. What is the magnitude of the average velocity during the interval from t = 11.9 s and t = 16.9 s.
The answer here is 1.30 m/s
I need help with:
What is the magnitude of the instantaneous velocity at t = 11.9 s?
What is the magnitude of the instantaneous acceleration at t = 16.9 s?
Thanks.
1 answer