Asked by Keeley

TRIANGLE ACE IS A CIRCUMSCRIBED TRIANGLE. POINTS B,D AND F ARE POINTS OF TANGENCY . IF AC= 16 AND AE= 9 CM AND CE = 15 CM FIND AD, FE, AND CD.

Thank you very mych
Answered by Steve
You don't explain the labeling very well, but I get that
AC is divided into 5+11
CE is divided into 11+4
AE is divided into 4+5
Answered by Keeley
but whats x ?
Answered by Reiny
Who knows ?
You don't mention x in your description.

You don't mention where B, D, and F are located, but I must have labeled mine the same way as Steve, since I got his answers as well.

What still has to be found is AD

In triangle ACE
9^2 = 16^2 + 15^2 - 2(15)(16)cosC
you should get cosC = 5/6
(don't find the actual angle)

in triangle ACD
AD^2 = 11^2 + 16^2 - 2(11)(16)cosC
= 251/3

AD = √(251/3) or appr 9.15
Answered by Steve
I assumed AD was a typo, or due to label discrepancy, since the subject is the tangents, which are of length 4,5,11.
Answered by Bebe
How do you find 4,5, and 11 though?
There are no AI answers yet. The ability to request AI answers is coming soon!