Asked by Lindsay
Use the information to evaluate and compare (triangle)x and dy.
y=2-x^4, x=2, and (triangle)x=dx=0.01
y=2-x^4, x=2, and (triangle)x=dx=0.01
Answers
Answered by
Steve
Surely by now you know that ∆ is pronounced "delta".
At x=2,
∆y = f(x+∆x)-f(x) = (2-2.01^4)-(0) = 0.3224
dy = -4x^3 dx = -4(8)(-.01) = 0.32
At x=2,
∆y = f(x+∆x)-f(x) = (2-2.01^4)-(0) = 0.3224
dy = -4x^3 dx = -4(8)(-.01) = 0.32
Answered by
Lindsay
I know that; don't know why I didn't use it. Oops.
How do you get 0 from f(x)?
How do you get 0 from f(x)?
Answered by
Steve
oops. I read x^2-4, not 2-x^4.
So, that would be -14, not 0.
Sorry...
Dang dyslexia (not really, just careless)
So, that would be -14, not 0.
Sorry...
Dang dyslexia (not really, just careless)
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