assuming all these buildings are the same one, if the building is at distance d from the tree of height h,
draw a diagram to see that
(150-h)/d = tan 50°
h/d = tan 22°
plugging in the numbers,
h+1.19d = 150
h = 0.40d
So, we have
h = 94.3
d = 37.7
From the foot of a building I have to look upwards at an angle of 22° to sight the top of a tree. From the top of a building, 150 meters above ground level, I have to look down at an angle of depression of 50° to look at the top of the tree.
a. How tall is the tree?
b. How far from the building is the tree?
1 answer