Asked by Timothy
A skydiver falls in air reaching terminal velocity, he shouts to his friend at 2000 Hz. His friend receives it at 2355 Hz, what is the divers speed?
Answers
Answered by
Henry
F = ((Vs+Vr)/(Vs-Vd))*Fd = 2355 Hz.
((343+0)/(343-Vd))*2000 = 2355
((343)/(343-Vd))*2000 = 2355
686000/(343-Vd) = 2355
2355(343-Vd) = 686000
343-Vd = 291.3
-Vd = 291.3-343 = -51.7
Vd = 51.7 m/s = Velocity of the diver.
((343+0)/(343-Vd))*2000 = 2355
((343)/(343-Vd))*2000 = 2355
686000/(343-Vd) = 2355
2355(343-Vd) = 686000
343-Vd = 291.3
-Vd = 291.3-343 = -51.7
Vd = 51.7 m/s = Velocity of the diver.
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