Asked by anabelle need help!
the three verticies of a triangle can be found at the points A(2,3) , B(-3,6), C(-4,-3)
how long is each side of the triangle ab,bc,and ac explain how you got the answer.
is this triangle a right triangle ? why and explain.
how long is each side of the triangle ab,bc,and ac explain how you got the answer.
is this triangle a right triangle ? why and explain.
Answers
Answered by
Steve
AB^2 = (-3-2)^2 + (6-3)^2 = 25+9 = 34
AC^2 = (-4-2)^2 + (-3-3)^2 = 36+36 + 72
BC^2 = (-4+3)^2 + (-3-6)^2 = 1+81 = 82
take square root to get the actual side lengths.
If ABC is a right triangle, we'd need 34+72=82, but it does not.
AC^2 = (-4-2)^2 + (-3-3)^2 = 36+36 + 72
BC^2 = (-4+3)^2 + (-3-6)^2 = 1+81 = 82
take square root to get the actual side lengths.
If ABC is a right triangle, we'd need 34+72=82, but it does not.
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