Asked by Liz
three circles are manually tangent externally. their centers form a triangle whose sides are of length 8, 9, 13. find the total area of the three circles
Answers
Answered by
Steve
If the radii of the circles are x,y,z then each side of the triangle is the sum of two of the radii. So,
x+y=8
x+z=9
y+z=13
(x,y,z) = (2,6,7)
Since the area of a circle is πr^2, the area of all of the circles is
π(2^2+6^2+7^2) = 89π
x+y=8
x+z=9
y+z=13
(x,y,z) = (2,6,7)
Since the area of a circle is πr^2, the area of all of the circles is
π(2^2+6^2+7^2) = 89π
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