Asked by Raj
∫[dy/(y^2-1)]
How do i solve this?
How do i solve this?
Answers
Answered by
Steve
standard trig substitution
Just as
∫[dy/(1+y^2)] = arctan(y),
∫[dy/(1-y^2)] = arctanh(y)
Just as
∫[dy/(1+y^2)] = arctan(y),
∫[dy/(1-y^2)] = arctanh(y)
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