Factor:

Question

(x^3)(z^6)-27y^9

81x^4-16y^4

2x^3+16y^3

Answer 1

You have the usual sum/difference of squares/cubes.

(xz^2)^3 - (3y^3)^3
= (xz^2-3y^3)((xz^2)^2 + (xz^2)(3y^3) + (3y^3)^2)

Similarly, the others are

(9x^2)^2 - (4y^2)^2
and
2(x^3 + (2y)^3)

Just apply your formulas. If you get stuck, come on back and say where.