Asked by laura
A boy jumps at a speed of 16.0 m/s at an angle of 20.0 above the horizontal. How long does he stay in the air before touching the ground?
A.
1.53 s
B.
1.12 s
C.
3.07 s
D.
4.2 s
A.
1.53 s
B.
1.12 s
C.
3.07 s
D.
4.2 s
Answers
Answered by
Henry
Vo = 16m/s[20o]
Yo = 16*sin20 = 5.47 m/s.
Y = Yo + g*t = 0 At max. Ht.
5.47 - 9.8t = 0
9.8t = 5.47
Tr = 0.558 s. = Rise time
Tf = Tr = 0.558 s. = Fall time.
T = Tr+Tf = 0.558 + 0.558 = 1.12 s.
Yo = 16*sin20 = 5.47 m/s.
Y = Yo + g*t = 0 At max. Ht.
5.47 - 9.8t = 0
9.8t = 5.47
Tr = 0.558 s. = Rise time
Tf = Tr = 0.558 s. = Fall time.
T = Tr+Tf = 0.558 + 0.558 = 1.12 s.
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