Asked by K
A crate is dragged 5.0 along a rough floor with a constant velocity by a worker applying a force of 125N to a rope at an angle of 30degrees to the horizontal.
Calculate the work done by the tension in the rope, the force of friction, and the net force. I know the work don on the weight of the crate and the normal force is 0J. Thanks for your help, and if possible show work, thanks!
Calculate the work done by the tension in the rope, the force of friction, and the net force. I know the work don on the weight of the crate and the normal force is 0J. Thanks for your help, and if possible show work, thanks!
Answers
Answered by
Damon
Tension force in the direction of motion = 125 cos 30
= 108 N
Work done by rope tension =
Tension force in the direction of motion times distance moved = 108*5 = 541 Joules
Since the velocity is constant, the horizontal tension force, 108 N is equal and opposite to the friction force.
Therefore if the tension force is positive, the friction force is -108 N
The crate is not accelerating.
F = m a
a is zero
therefore
the net force on the crate is zero.
= 108 N
Work done by rope tension =
Tension force in the direction of motion times distance moved = 108*5 = 541 Joules
Since the velocity is constant, the horizontal tension force, 108 N is equal and opposite to the friction force.
Therefore if the tension force is positive, the friction force is -108 N
The crate is not accelerating.
F = m a
a is zero
therefore
the net force on the crate is zero.
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