Asked by jm
An ore sample with a mass of 670 kg contains 27.7% magnesium carbonate .If all of the magnesium carbonate in this ore sample is decomposed to form carbon dioxide ,describe how to determine what mass of carbon dioxide is evolved during the process.
Answers
Answered by
Steve
magnesium carbonate is MgCO3
So, each molecule will produce a molecule of CO2
27% of 670kg is 180.9kg
each mole of MgCO3 has a mass of 84.3g, so we have 2145.9 moles of MgCO3.
That will produce 2145.9 moles of CO2, each with a mass of 44g.
So, each molecule will produce a molecule of CO2
27% of 670kg is 180.9kg
each mole of MgCO3 has a mass of 84.3g, so we have 2145.9 moles of MgCO3.
That will produce 2145.9 moles of CO2, each with a mass of 44g.
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