Find the exact solutions on the interval [0,pi].
2sin2x = sqrt(x)
Please help me!
kristie, this problem is somewhere between a calculus problem and an algebra one. I'm not sure what you're taking. If you see that the eq. is = to 4(sin2x)^2=x , then you might see where they're equal graphically. I think they want you to make use of the lim sinX / X for this exercise too.
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