Question

Find the exact solutions on the interval [0,pi].

2sin2x = sqrt(x)

Please help me!


kristie, this problem is somewhere between a calculus problem and an algebra one. I'm not sure what you're taking. If you see that the eq. is = to 4(sin2x)^2=x , then you might see where they're equal graphically. I think they want you to make use of the lim sinX / X for this exercise too.

Related Questions

I have to find an exact solutions on the interval [0,pi) for both of these problems-- 1) 2sin2x =... I need to find the exact solution to: 2sin2x = sqrt(x)on the interval (0,pi) This is how I sta... Find all the solutions in the interval [0,2pi). 2sin2x - sqrt(2) = 0 sin2x = sqrt(2)/2 I'm... find the exact solutions in the interval [0,2pi), sin4x=-2sin2x