Asked by jerson
gont get it.. To what temp must a sample of nitrogen at 27 degrees C and 0.625 atm be taken so that its pressure becomes 1.125 atm at constant volume
i used the formula and it still gave me a weird answer
i used the formula and it still gave me a weird answer
Answers
Answered by
DrBob222
P1/T1 = P2/T2
T must be in Kelvin.
T must be in Kelvin.
Answered by
jerson
i still don't get it tho. is it 0.625*27/1.125?
Answered by
DrBob222
Did you see my note about using Kelvin? The 27 is degrees C. It must be changed to KELVIN? Do you know how to do that? ALSO, you didn't multiply right (or you set up the equation wrong).
Make a table
Pressure Temperature
1.125........??
0.625........27 (change to Kelvin).
To solve you cross multiply the ratios.
Make a table
Pressure Temperature
1.125........??
0.625........27 (change to Kelvin).
To solve you cross multiply the ratios.
Answered by
jerson
oooh so 1.125 * 27/0.625
Answered by
DrBob222
You have the multiplication down BUT you didn't change T of 27 C to KELVIN!
Answered by
jerson
i don't know how to do that
Answered by
DrBob222
Kelvin = 273.15 + C.
Answered by
jerson
for this one i did
0.625....27+273= 300
1.125... T2
0.625=1.125
300= T2
1.125*300/0.625=540?
0.625....27+273= 300
1.125... T2
0.625=1.125
300= T2
1.125*300/0.625=540?
Answered by
DrBob222
That looks ok to me.
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