Asked by Collin
Consider an aluminum wire with 1 mm diameter below its critical temperature of 1.2 Kelvin. It's critical magnetic field is 0.01 Tesla. What is the maximum current in Amps that you can send down this wire for it to remain superconducting?
Answers
Answered by
Elena
r=d/2 =0.5 mm =0.0005 m
I(max) = B(cr) c r /2 = 0.01•3•10⁸•0.0005 /2 = 750 A
I(max) = B(cr) c r /2 = 0.01•3•10⁸•0.0005 /2 = 750 A
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.