Asked by HELP
Of the parts produced by a particular machine, 1.5% are defective. If a random sample of 11 parts produced by this machine contains 2 or more defective parts, the machine is shut down for repairs. Find the probability that the machine will be shut down for repairs based on this sampling plan.
Answers
Answered by
Kuai
1-p(x = 0) + p(x = 1)
1-[(11C0)(.015)^0(.985)^11 + 11C1 *0.015^1 *.985^10)]
1-[.84684 + .14185]
1-.9887 = 0.0113
1-[(11C0)(.015)^0(.985)^11 + 11C1 *0.015^1 *.985^10)]
1-[.84684 + .14185]
1-.9887 = 0.0113