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The proportion of adults living in a small town who are college graduates is estimated to be p = 0.6. To test this hypothesis,...Asked by Katy
The proportion of adults living in a small town who are college graduates is estimated to be p = 0.6. To test this hypothesis, a random sample of 15 adults is selected. If the number of college graduates in the sample is anywhere from 6 to 12, we shall not reject the null hypothesis that p = 0.6; otherwise, we shall conclude that p /= 0.6.
Evaluate β for the alternatives p = 0.5 and p = 0.7.
Beta is The probability of Type 2 error.
I tried to use the binomial distribution with n=15 and p=.5 and .7 to get P(6<=x<=12|p=.5) and use 12 and 6 for x and substract the results but I can't get the correct answers which are 0.8454 for p=0.5, and 0.8695 for p=0.7
Is there another way of doing it? Are my x's right for the binomial distribution right?
Evaluate β for the alternatives p = 0.5 and p = 0.7.
Beta is The probability of Type 2 error.
I tried to use the binomial distribution with n=15 and p=.5 and .7 to get P(6<=x<=12|p=.5) and use 12 and 6 for x and substract the results but I can't get the correct answers which are 0.8454 for p=0.5, and 0.8695 for p=0.7
Is there another way of doing it? Are my x's right for the binomial distribution right?
Answers
Answered by
C. Fenwick
Suppose that the antenna lengths of woodlice are approximately normally distributed with a mean of 0.2 inches and a standard deviation of 0.05 inches. What proportion of woodlice have antenna lengths that are more than 0.23 inches? Round your answer to at least four decimal places.