Asked by David
find the exact value of tan 2β if sin β=5/13 (β in quadrant II)
Answers
Answered by
Steve
tanβ = -5/12
tan2β = 2tanβ/(1-tan^2β)
= 2(-5/12)/(1-25/144)
= -120/119
tan2β = 2tanβ/(1-tan^2β)
= 2(-5/12)/(1-25/144)
= -120/119
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