Asked by Donna
To measure the static friction coefficient between a 1.6-kg block and a vertical wall, the setup shown in the drawing is used. A spring (spring constant = 400 N/m) is attached to the block. Someone pushes on the end of the spring in a direction perpendicular to the wall until the block does not slip downward. The spring in such a setup is compressed by 0.050 m. What is the coefficient of static friction?
Answers
Answered by
Henry
F1 = m*g = 1.6kg * 9.8N/kg = 15.68 N
F2 = (0.05m/1m) * 400N = 20 N.
F1-Fs = m*a
15.68-Fs = m*0 = 0
Fs = 15.68 = Force of static friction.
Fs = u*F2 = 15.68
u*20 = 15.68
u = 0.784 = Coefficient of static friction.
F2 = (0.05m/1m) * 400N = 20 N.
F1-Fs = m*a
15.68-Fs = m*0 = 0
Fs = 15.68 = Force of static friction.
Fs = u*F2 = 15.68
u*20 = 15.68
u = 0.784 = Coefficient of static friction.
Answered by
jenny
forrest's mama said life is like a box of chocolates. you never which physics problem youre gonna get. also me and forrest were like peas and carrots
Answered by
jenny
no <3
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