If f(x)=5x^3–2/x^4
find f'(x)
I don't understand what I did wrong for this
((x^4)(4x+7)-(4x^3)(5x^3-2))/(x^4)^2
4 answers
Now reduce the x powers. I see righ toff you can remove an x^3 power.
(4x^2+7x-12)/x^8 ??
No
Let me guide you through the u/v rule.
d(u/v)=( udv + vdu ) /v^2
u= 5x^2-2 du=10x
v=x^4 dv=4x^3
f'= (5x^2+2)x^4 + 10x(4x^3) / x^8
= ((5x^2+2) + 40))/x^4
no gather the terms, and do the quadratic. Check my typing
Let me guide you through the u/v rule.
d(u/v)=( udv + vdu ) /v^2
u= 5x^2-2 du=10x
v=x^4 dv=4x^3
f'= (5x^2+2)x^4 + 10x(4x^3) / x^8
= ((5x^2+2) + 40))/x^4
no gather the terms, and do the quadratic. Check my typing
d/dx (5x^3–2) = 15 x^2
not what you wrote
not what you wrote