Asked by Barbara Passmore
The zero factor property; Can you help with this problem?
W^2 + 4w^2 -4w=16
W^2 + 4w^2 -4w=16
Answers
Answered by
Jai
Are you sure the first term is w^2 or w^3?
Anyway, if it's w^3,
w^3 + 4w^2 - 4w = 16
w^3 + 4w^2 - 4w - 16 = 0
w^2(w + 4) - 4(w + 4) = 0
(w^2 - 4)(w + 4) = 0
(w + 2)(w - 2)(w + 4) = 0
w = -2
w = 2
w = -4
Hope this helps :3
Anyway, if it's w^3,
w^3 + 4w^2 - 4w = 16
w^3 + 4w^2 - 4w - 16 = 0
w^2(w + 4) - 4(w + 4) = 0
(w^2 - 4)(w + 4) = 0
(w + 2)(w - 2)(w + 4) = 0
w = -2
w = 2
w = -4
Hope this helps :3
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