LS = (tanx - tan(π/4)/(1 + tanx(tan(π/4)) )
= (tanx - 1)/(1 + tanx)
= RS
I used the identity
tan(A-B)= (tanA - tanB)/(1 + tanAtanB)
and the fact that tan π/4 = tan 45°= 1
Prove the identity. (show your work please)
tan(x − π/4)= (tan x − 1)/(tan x + 1)
Thank you!
1 answer