Question

3. You travel from New Orleans, Louisiana, with the following vectors:
• New Orleans à Point A: q = 180°, Δd = 483 km
• Point A à Point B: q = 106°, Δd = 347 km
• Point B à Point C: q = 106°, Δd = 347 km
Remember: east = 0°, north = 90°, west = 180
Use the map to find your final destination. Where is the final destination, and what is its displacement from New Orleans? Show a data table containing each vector and its x and y components. Include the values of Δdnetx, Δdnety, Δdnet, tan qr, and qr.

Answer 1

d = 483[180o ] + 347[106o] + 347[106o]
d = 483[180 + 694[106o]

X = 483*cos180 + 694*cos106 = -674.3 km
Y = 483*sin180 + 694*sin106 = 667.1 km

tan Ar = Y/X = 667.1/-674.3 = -0.98935
Ar = -44.69o = Reference angle.

A = 180-44.69 = 135.3o

d = X/cosA = -674.3/cos135.3 = 948.7 km
[135.3] = Final destination.

Disp. = 948.7[135.3o] - 483[180o]
X=948.7*cos135.3 - 483*cos180=-191.3 km
Y=948.7*sin135.3 - 483*sin180 = 667.3 km

tan Ar = Y/X = 667.3/-191.3 = -3.48829
Ar = -74o = Reference angle.
A = -74 + 180 = 106o

Disp. = Y/sinA = 667.3/sin106 = 694.2km[106o].

Answer 2

i don't get it