Question

9(q+1)+6(q+1)^2

7(a-b)(a+b)-14(a+b)

4x^2(x+1)-6x(x+1)

Answer 1

do the same way as in the previous post. Just factor out repeated values, as in

7(a-b)(a+b) - 14(a+b)
7(a+b)(a-b-2)

Answer 2

9(q+1)+6(q+1)^2
=
9q +9 + 6q^2 + 16q + 6

=6q^2 + 25q + 15

7(a-b)(a+b)-14(a+b)
=
7(a^2 + ab -ab -b^2) -14a -14b

=7a^2 -7b^2 -14a -14b


4x^2(x+1)-6x(x+1)
=
4x^3 + 4x^2 -6x^2 -6x
=
4x^3 -2x^2 -6x