Asked by koala
Determine for solid manganese (Mn) the following:
What is the atomic density (atoms/m) along the [110] direction of the Mn crystal?
What are the number of nearest neighbors around an atom in the Mn crystal?
Calculate the interplanar spacing (m) between {220} planes in the Mn crystal.
What is the atomic density (atoms/m) along the [110] direction of the Mn crystal?
What are the number of nearest neighbors around an atom in the Mn crystal?
Calculate the interplanar spacing (m) between {220} planes in the Mn crystal.
Answers
Answered by
DDD
For molibdenium
We see from the PT that Mo is a BCC material, so the face diagonal [011] has 2⋅(12) atoms over a distance of 2√a.
The value of the lattice parameter a can be found in the same manner as the previous problem (noting that the BCC structure has only 2 atoms per unit cell rather than 4). Thus,
1 atom2√a=12√(2VmolarNAv)1/3=2.24×107
We see from the PT that Mo is a BCC material, so the face diagonal [011] has 2⋅(12) atoms over a distance of 2√a.
The value of the lattice parameter a can be found in the same manner as the previous problem (noting that the BCC structure has only 2 atoms per unit cell rather than 4). Thus,
1 atom2√a=12√(2VmolarNAv)1/3=2.24×107
Answered by
gg
2.44e9
Answered by
WilliamIsaDickinson
gg is right
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.