Question
A 14.9-kg object hangs in equilibrium at the end of a rope (taken as massless) while a wind pushes the object with a 67.7-N horizontal force. Find the tension in the rope and the rope\'s angle from the vertical. The acceleration due to gravity is 9.81 m/s2.
Answers
Elena
x: F=Tsinα
y: mg=Tcosα
F/mg=Tsinα/ Tcosα
tanα =F/mg=67.7/14.9•9.8 = 0.46
α =arctan0.46= 24.9⁰
T=F/sinα=67.7/sin24.9=67.7/0.42=161 N
y: mg=Tcosα
F/mg=Tsinα/ Tcosα
tanα =F/mg=67.7/14.9•9.8 = 0.46
α =arctan0.46= 24.9⁰
T=F/sinα=67.7/sin24.9=67.7/0.42=161 N