Question

A charged particle of mass 8.39×10−4 kg starts from rest and accelerates through a potential difference of +25,000 V to reach a speed of 1170 m/s. What is the charge on this particle?
QV= 1/2(mv^2)
Q is the charge
V= potential
V= speed
m= mass
Q * 25000= 0.5 * 0.000839* 1170* 1170
Q= 574/ 25000= 0.023 C

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