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An ocean liner is traveling at 5m/s. A passenger on deck walks towards the rear of the ship at a rate of 4m/s. After walking 30...Asked by Connor
An ocean liner is traveling at 5m/s. A passenger on deck walks towards the rear of the ship at a rate of 4m/s. After walking 30 meters, he turns right and walks at a rate of 4m/s to the rail, which is 12 meters from his turning point.
What is his velocity relative to the water surface while walking to the rear and his velocity while walking toward the rail?
What was his total displacement from his starting point?
Please help me solve this. I do not know how to solve this challenging problem.
What is his velocity relative to the water surface while walking to the rear and his velocity while walking toward the rail?
What was his total displacement from his starting point?
Please help me solve this. I do not know how to solve this challenging problem.
Answers
Answered by
bobpursley
velocity relative to ship+velocityship relative water=velocityrelativeto water.
a.-4+5=1m/s
b. velocity walking across=sqrt(5^2+4^2)
a.-4+5=1m/s
b. velocity walking across=sqrt(5^2+4^2)
Answered by
Connor
Then how would I find the toatl displacement from starting point?
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