A 1400-kg race car can go from 0 to 90km/h in 6.0s . What average power is required to do this?

Answer 1

V = 90km/h = 90000m/3600s = 25 m/s.

a = (V-Vo)/t = (25-0)/6 = 4.167 m/s^2

d = 0.5a*t^2 = 0.5*4.167*6^2 = 75 m.

P = F*d/t = mg * d/t
P = 13720 * 75/6 = 171,500 J/s.